x^2(2-x)+(x-2)^3=-5(1-2x)+(2x+1)(1-2x)

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Solution for x^2(2-x)+(x-2)^3=-5(1-2x)+(2x+1)(1-2x) equation: 



x^2(2-x)+(x-2)^3=-5(1-2x)+(2x+1)(1-2x)

We move all terms to the left:

x^2(2-x)+(x-2)^3-(-5(1-2x)+(2x+1)(1-2x))=0

We add all the numbers together, and all the variables

x^2(-1x+2)+(x-2)^3-(-5(-2x+1)+(2x+1)(-2x+1))=0

We multiply parentheses ..

x^2(-1x+2)-(-5(-2x+1)+(-4x^2+2x-2x+1))+(x-2)^3=0



We calculate terms in parentheses: -(-5(-2x+1)+(-4x^2+2x-2x+1)), so:

-5(-2x+1)+(-4x^2+2x-2x+1)

determiningTheFunctionDomain
(-4x^2+2x-2x+1)-5(-2x+1)

We multiply parentheses

(-4x^2+2x-2x+1)+10x-5

We get rid of parentheses

-4x^2+2x-2x+10x+1-5

We add all the numbers together, and all the variables

-4x^2+10x-4

Back to the equation:

-(-4x^2+10x-4)



We get rid of parentheses

x^2(-1x+2)+4x^2-10x+(x-2)^3+4=0

We add all the numbers together, and all the variables

4x^2+x^2(-1x+2)-10x+(x-2)^3+4=0

We move all terms containing x to the left, all other terms to the right

4x^2+x^2(-1x+2)-10x+(x-2)^3=-4

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